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For a moving object, the force acting on the object varies directly with the object's acceleration. When a force of 64 N acts on a certain object, the acceleration of the object is 8 /ms2. If the acceleration of the object becomes 5 /ms2, what is the force? n=

Sagot :

Explanation

From Newton's Law, we know that the force is given by:

[tex]F=M\cdot a.[/tex]

Where M is the mass object and a is the acceleration.

From the statement, we know that for a force F = 64 N, we have an acceleration a = 8 m/s², replacing this data in the equation above, we have:

[tex]64N=M\cdot8\text{ }m/s^2.[/tex]

Solving for m, we get:

[tex]M=\frac{64N}{8\text{ }m/s^2}=8kg.[/tex]

Where we have used the fact that N = kg m/s².

Now, using the value M = 8 kg, for an acceleration a' = 5 m/s², we have a force:

[tex]F^{\prime}=M\cdot a^{\prime}=8kg\cdot5m/s^2.=40N.[/tex]Answer

The new value of the force is 40 N.