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The vertices of ABC are A(5. - 3), B(-5,- 1), and C(1,1). For the translation below, give the vertices of AA'B'C'. T(1,2) (ABC) The vertices of AA'B'C' are A' B' and C (Simplify your answers. Type ordered pairs.)

The Vertices Of ABC Are A5 3 B5 1 And C11 For The Translation Below Give The Vertices Of AABC T12 ABC The Vertices Of AABC Are A B And C Simplify Your Answers T class=

Sagot :

Answer:

A'(6,-1), B'(-4,1) and C'(2,3)

Explanation:

The vertices of triangle ABC are: A(5, - 3), B(-5, - 1), and C(1, 1).

The translation rule is interpreted below:

[tex](x,y)\rightarrow(x+1,y+2)[/tex]

Therefore, the vertices of the image of ABC will be:

[tex]\begin{gathered} A^{\prime}(5+1,-3+2)=(6,-1) \\ B^{\prime}(-5+1,-1+2)=(-4,1) \\ C^{\prime}(1+1,1+2)=(2,3) \end{gathered}[/tex]

The vertices of triangle A'B'C' are:

A'(6,-1), B'(-4,1) and C'(2,3)

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