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Sagot :
we have
y < -2/3x + 2 ------> inequality A
y < 1/2 x - 3 ------> inequality B
we have that
The solution of the inequality A is the shaded area below the dashed line y=-2/3x+2
The solution of the inequality B is the shaded area below the dashed line y=1/2x-3
so the solution for the system of inequalities, is the shaded area below the two dashed lines
see the attached figure to better understand the problem
please wait a minute
therefore
the point (-3,-10) satisfy both inequalities
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