Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Discover in-depth answers to your questions from a wide network of professionals on our user-friendly Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

What is an equation of a line (in slope-intercept form) that passes through the points (4,0) and-2, 1)?

Sagot :

Answer:

[tex]y=-\frac{x}{6}+\frac{4}{6}[/tex]

Step-by-step explanation:

Equation of a line:

The equation of a line, in slope-intercept formula, is given by:

y = mx + b

In which m is the slope and b is the y-intercept.

To find the slope, we select two points. The slope is the change in y divided by the change in x.

In this question:

Points (4,0) and (-2,1) .

Change in y: 1 - 0 = 1

Change in x: -2 -4 = -6

So the slope is:

1/-6 = -1/6

The equation has the format:

y = (-1/6)x + b

Since it passes through the point (4,0), we have that when x = 4, y = 0. So

0 = (-1/6)*4 + b

b - 4/6 = 0

b = 4/6

So the equation of the line is:

[tex]y=-\frac{x}{6}+\frac{4}{6}[/tex]

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.