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Question 2: 11A triangle has a base length of 6ac? and a height 3 centimeters more than the base length. Find the aroa of thetriangle if a = 2 and c = 3.O 5,994 cm?O 3,078 cm?O 11,988 cm?O2,025 cm?

Question 2 11A Triangle Has A Base Length Of 6ac And A Height 3 Centimeters More Than The Base Length Find The Aroa Of Thetriangle If A 2 And C 3O 5994 CmO 3078 class=

Sagot :

Answer:

[tex]5,994cm^2[/tex]

Explanation:

Here, we want to get the area of the triangle

The area of the triangle is mathematically half the product of the base and the height of the triangle

From what we have, let us get the base length first. We simply proceed to susbtitute the values of the variables into the given expression

[tex]\begin{gathered} \text{ base = 6ac}^2 \\ \text{base = 6}\times2\times3^2\text{ = 108 cm} \end{gathered}[/tex]

The height is 3 cm more than this, so we have it as 108 cm + 3 cm = 111 cm

The area is thus calculated as follows:

[tex]\text{ Area = }\frac{1}{2}\times108\times111=5,994cm^2[/tex]