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The perimeter of the rectangle below is 112 units. Find the length of side AD Write your answer without variables. AD= 3x+3 DC = 4x-3

Sagot :

The perimeter of the rectangle below is 112 units.

Given :

AD = 3x + 3

DC = 4x - 3

So, the perimeter is:

[tex]2\cdot\lbrack(3x+3)+(4x-3)\rbrack=112[/tex]

solve for x:

First, divide the sides by 2

So,

[tex]\begin{gathered} (3x+3)+(4x-3)=\frac{112}{2} \\ \\ 3x+3+4x-3=56 \\ 7x=56 \\ \\ x=\frac{56}{7}=8 \end{gathered}[/tex]

so, the length of the side AD is:

[tex]AD=3x+3=3\cdot8+3=24+3=27[/tex]

So, the length of the side AD = 27 unit

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