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Assume that when adults with smartphones are randomly selected, 43% use them in meetings or classes. 17 at smartphone users are randomly selected, findprobability that exactly 2 of them use their smartphones in meetings or classes.

Sagot :

Binomial Distribution

The probability that a random adult with smartphones uses them in meetings or classes is p=43%, or p=0.43 when expressed as a decimal.

The probability that the selected adult is not using them in classes is q = 1 - p = 0.57.

The binomial distribution is used when two possible outcomes are expected from a repeating random experience.

In our case, the total number of experiments is n=17 and we want to compute the probability that exactly m=2 of them is successful. The formula is:

[tex]P=C_{m,n}\cdot p^mq^{m-n}[/tex]

Where C is the combinatorial formula:

[tex]C_{m,n}=\frac{m!}{n!\cdot(m-n)!}[/tex]

Substitute the given values in the formula:

[tex]P=\frac{17!}{2!\cdot15!}\cdot0.43^2\cdot0.57^{15}[/tex]

Calculating:

[tex]\begin{gathered} P=136\cdot0.1849\cdot0.0002178 \\ P=0.0055 \end{gathered}[/tex]

The probability is 0.0055 or 0.55%