Given:
length of rectangle = 17
Width of rectangle = 22
The base of the triangle = 19
Find -: Area of the figure.
Sol:
The area of a rectangle is:
[tex]\text{ Area = Length }\times\text{ Width}[/tex]So the area of a rectangle is:
[tex]\begin{gathered} \text{ Area =}\times17\times22 \\ \\ =374 \end{gathered}[/tex]Height of the triangle is:
[tex]\begin{gathered} \text{ H = }22-10 \\ \\ =12 \end{gathered}[/tex]Area of triangle is:
[tex]\begin{gathered} A=\frac{1}{2}\times\text{ Base}\times\text{ Height} \\ \end{gathered}[/tex][tex]\begin{gathered} A=\frac{1}{2}\times19\times12 \\ \\ A=6\times19 \\ \\ A=114 \end{gathered}[/tex]Area of figure is:
[tex]\begin{gathered} A=374+114 \\ \\ A=488 \end{gathered}[/tex]