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14. Find the area of the complex figure.17 cm10 cm17 cm192A.244cmB.488 cmC.379 cmD.583 cm

14 Find The Area Of The Complex Figure17 Cm10 Cm17 Cm192A244cmB488 CmC379 CmD583 Cm class=

Sagot :

Given:

length of rectangle = 17

Width of rectangle = 22

The base of the triangle = 19

Find -: Area of the figure.

Sol:

The area of a rectangle is:

[tex]\text{ Area = Length }\times\text{ Width}[/tex]

So the area of a rectangle is:

[tex]\begin{gathered} \text{ Area =}\times17\times22 \\ \\ =374 \end{gathered}[/tex]

Height of the triangle is:

[tex]\begin{gathered} \text{ H = }22-10 \\ \\ =12 \end{gathered}[/tex]

Area of triangle is:

[tex]\begin{gathered} A=\frac{1}{2}\times\text{ Base}\times\text{ Height} \\ \end{gathered}[/tex][tex]\begin{gathered} A=\frac{1}{2}\times19\times12 \\ \\ A=6\times19 \\ \\ A=114 \end{gathered}[/tex]

Area of figure is:

[tex]\begin{gathered} A=374+114 \\ \\ A=488 \end{gathered}[/tex]

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