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Sagot :
ANSWER:
C. Write each student's name on a slip of paper and put the slips in a bag. Randomly draw a slip of paper. The student whose name is on the paper wins.
D. Roll a number cube. If it lands on 1 or 3, Alina wins. If it lands on 2 or 4, Robert wins. If it lands on 5 or 6, Makayla wins.
STEP-BY-STEP EXPLANATION:
The ways in which a fair decision can be made about who goes to dinner, it must be taken into account that each one has the same possibilities and that all the scenarios are met.
Option A is not fair, for even numbers, there are 3 and for odd numbers there are 3, there are no chances for Makayla.
In option B, it is not taken into account that there are two events, and Robert has an advantage.
In option C, it is totally fair, everyone has the same chance.
Like option C, in option D the probabilities are the same in each case.
Therefore, the correct answers are:
C. Write each student's name on a slip of paper and put the slips in a bag. Randomly draw a slip of paper. The student whose name is on the paper wins.
D. Roll a number cube. If it lands on 1 or 3, Alina wins. If it lands on 2 or 4, Robert wins. If it lands on 5 or 6, Makayla wins.
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