Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Experience the ease of finding quick and accurate answers to your questions from professionals on our platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
Step 1
The reaction must be written and balanced:
4Cs + O2 → 2Cs2O
---------------
Step 2
Determine the limiting reactant:
The molar mass Cs) 133 g/mol
The molar mass O2) 32 g/mol
4Cs + O2 → 2Cs2O
Procedure:
4 x 133 g Cs ------ 32 g O2
46.1 g Cs ------ X = 2.77 g O2 is needed
("----" means 4 x 133 grams of Cs reacts to 32 g of O2)
For 46.1 g Cs, 2.77 g O2 is needed, but there is 13.4 g O2. Therefore, the limiting reactant is Cs.
-------------
Step 3
Determine the theoretical yield of Cs2O from Cs:
4Cs + O2 → 2Cs2O
The molar mass Cs2O) 282 g/mol
Procedure:
4 x 133 g Cs ----- 2 x 282 g/mol Cs2O
46.1 g Cs ----- X = 48.8 g Cs2O = theoretical yield
----------
Step 4
% yield is defined as = actual yield/theoretical yield x 100
The actual yield is already provided = 28.3 g Cs2O
So, % yield = 28.3 g/48.8 g x 100 = 58 % approx.
Answer: % yield = 58 %
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.
