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Sagot :
Given data:
* The coefficient of static friction is,
[tex]\mu_s=0.46[/tex]* The mass of the fridge is m = 100 kg.
Solution:
The normal force acting on the fridge is,
[tex]\begin{gathered} F_N=mg \\ F_N=100\times9.8 \\ F_N=980\text{ N} \end{gathered}[/tex]The frictional force acting on the fridge is,
[tex]\begin{gathered} F_r=\mu_s\times F_N \\ F_r=0.46\times980 \\ F_r=450.8\text{ N} \end{gathered}[/tex]The force required to start moving the fridge is equal to the frictional force.
Thus, the force required in the given case is 450.8 N.
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