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Sagot :
Let:
A = land on heads
B = rolling a 1, 2, or a 4 on a die
so:
[tex]P(A)=\frac{1}{2}[/tex]since the coin needs to land on heads 3 times:
[tex]P(A3)=P(A)\cdot P(A)\cdot P(A)=(\frac{1}{2})^3=\frac{1}{8}[/tex]and rolling a 1, 2, or a 4 on a die:
[tex]\begin{gathered} P(B)=\frac{3}{6}=\frac{1}{2} \\ so\colon \\ P(A3)\cdot P(B)=\frac{1}{8}\cdot\frac{1}{2}=\frac{1}{16} \end{gathered}[/tex]
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