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Sagot :
To find the answer to this question, we have to use the quadratic formula:
[tex]x=\frac{-b^\pm\sqrt{b^2-4ac}}{2a}[/tex]In this case, a has a value of 3, b has a value of -7 and c has a value of 11, replace for the given values:
[tex]\begin{gathered} x=\frac{-(-7)^\pm\sqrt{(-7)^2-4(3)(11)}}{2(3)} \\ x=\frac{7\pm\sqrt{49-132}}{6} \\ x=\frac{7\pm\sqrt{-83}}{6} \\ x=\frac{7\pm\sqrt{83}i}{6} \\ x1=\frac{7+\sqrt{83}i}{6} \\ x2=\frac{7-\sqrt{83}i}{6} \end{gathered}[/tex]It means that the solutions of the equation are (7+√83i)/6 and (7-√83i)/6
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