Answered

Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Discover a wealth of knowledge from experts across different disciplines on our comprehensive Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

16 in12 inOriginal3 in20 in5 inHow do the perimeters of the similarshapes above compare?

Sagot :

The original has dimensions 16 in, 12 in and 20 in.

The image has dimensions 3 in, 4 in and 5 in.

We need to find the perimeter of both triangles and then compare them.

The perimeter of a triangle is given as:

P = a + b + c

where a, b, c are the three sides of the triangle

Therefore, the perimeter of the original is:

P = 16 + 12 + 20 = 48 in

The perimeter of the image is:

p = 3 + 4 + 5 = 12 in

By comparing these two perimeters, we can see that the perimeter of the original is 4 times that of the image.

So the image's perimeter is 1/4 that of the original. (Option B)

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.