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A seismic wave has a frequency of 452 Hz and a wavelength of 38 meters. What is the velocity of the wave in the nearest meter per second?

Sagot :

Answer:

17176 m/s

Explanation:

The velocity of the wave can be calculated as

v = λf

Where λ is the wavelength and f is the frequency.

Replacing λ = 38 m and f = 452 Hz, we get

v = (38 m)(452 Hz)

v = 17176 m/s

Therefore, the answer is

17176 m/s