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Sagot :
EXPLANATION
Let's see the facts:
Number of adults = 693
-58% would erase the personal information.
-100%-58% = 42% would not erase their personal information.
n= 693
p=58% = 0.58
As we can see, 58% represents the proportion of a sample and thus we are making a claim about a population proportion p in the hypotheses.
It says "most of the adults", so it would be p>0.5
The null hypotheses states that the population proportion is equal to the value mentioned in the claim.
H0 : p=0.5
Then, q=1-p = 1-0.5 = 0.5
Now, the test statistic will be:
[tex]\frac{\vec{p}-p}{\sqrt[]{\frac{pq}{n}}}=\frac{0.58-0.5}{\sqrt[]{\frac{0.5\cdot0.5}{693}}}=\frac{0.08}{\sqrt[]{\frac{0.25}{693}}}=\frac{0.08}{\sqrt[]{\frac{1}{2772}}}=4.211[/tex]Answer: the test statistic is equal to 4.211
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