Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Join our platform to connect with experts ready to provide accurate answers to your questions in various fields. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

Allie found a table of data displaying the number of middle and high school stud enrolled in Lincoln public schools . she made a table with the number of students in the 2015 as year 0 in the table of data.Lookimh at the enrollment in previous years,she decided to use an exponential equation to model the number of students.⚠COULD SOMEONE PLEASE HELP WITH THESE QUESTIONS⚠(Any info will help!!)⛧What is the growth multiplier for the data? complete the table using the multiplier.⛧⛧Write multiplier as a percent.⛧

Allie Found A Table Of Data Displaying The Number Of Middle And High School Stud Enrolled In Lincoln Public Schools She Made A Table With The Number Of Students class=

Sagot :

The general exponential growth formula is:

[tex]y=a\cdot b^x^{}[/tex]

where a is the initial amount, b is the growth multiplier, and y and x are the variables.

In this case, x represents years after 2015, y represents the number of students, and the initial value is a = 20,080.

Substituting with y = 20,582 when x = 1, we get:

[tex]\begin{gathered} 20,582=20,080\cdot b^1 \\ \frac{20.582}{20,080}=b \\ 1.025=b \end{gathered}[/tex]

Now, we can complete the table as follows:

[tex]\begin{gathered} x=2 \\ y=20,080\cdot1.025^2=21097 \\ x=3 \\ y=20,080\cdot1.025^3=21624 \\ x=4 \\ y=20,080\cdot1.025^4=22165 \end{gathered}[/tex]

Expressing the exponential growth formula with the rate of growth r:

[tex]y=a(1+r)^x^{}[/tex]

where b has been replaced by 1 + r. This means that r = 0.025, which expressed as a percent is 0.025*100 = 2.5% growth