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Square binomial using Binomial Squares Pattern (simplify) ( x + 6/7)^2

Sagot :

We need to simplify the expression:

[tex]\mleft(x+\frac{6}{7}\mright)^2[/tex]

We can use the following identity:

[tex](a+b)^{2}=a^{2}+2ab+b^{2}[/tex]

In this problem, we have:

[tex]\begin{gathered} a=x \\ \\ b=\frac{6}{7} \end{gathered}[/tex]

Thus, we obtain:

[tex]\begin{gathered} \mleft(x+\frac{6}{7}\mright)^2=x^2+2\cdot x\cdot\frac{6}{7}+\mleft(\frac{6}{7}\mright)^2 \\ \\ \mleft(x+\frac{6}{7}\mright)^2=x^{2}+\frac{12}{7}x+\frac{36}{49} \end{gathered}[/tex]

Therefore, after simplifying, we obtain:

[tex]x^2+\frac{12}{7}x+\frac{36}{49}[/tex]

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