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Sagot :
1) Chemical equation
[tex]Na_2S_2O_{3(aq)}+4Cl_{2(g)}+5H_2O\rightarrow2NaHSO_{4(aq)}+8HCl_{(aq)}[/tex]2) Moles of Na2S2O3 needed to react with Cl2 (a).
The molar ratio
1 mol Na2S2O3: 4 mol Cl2
[tex]molNa_2S_2O_3=0.36molCl_2\cdot\frac{1molNa_2S_2O_3}{4molCl_2}=0.09molNa_2S_2O_3[/tex](a) We need 0.09 mol Na2S2O3 to react with 0.36 mol Cl2.
3) Moles of HCl formed from Cl2 (b).
The molar ratio
8 mol HCl: 4 mol Cl2
[tex]molHCl=_{}0.19molCl_2\cdot\frac{8molHCl_{}}{4molCl_2}=0.38molHCl[/tex](b) 0.19 mol Cl2 can form 0.38 mol HCl
4) Moles of H2O required for the reaction of Cl2 (c).
The molar ratio
5 mol H2O: 4 mol Cl2
[tex]molH_2O=0.46molCl_2\cdot\frac{5molH_2O}{4molCl_2}=0.575molH_2O[/tex](c) 0.575 mol H2O are required for the reaction of 0.46 mol Cl2.
5) Moles of H2O to form HCl
The molar ratio
5 mol H2O: 8 mol HCl
[tex]mol_{}H_2O=0.39molHCl\cdot\frac{5molH_2O}{8molHCl_{}}=0.24375molH_2O_{}[/tex](d) 0.24375 mol H2O is needed to form 0.39 mol HCl.
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