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Sagot :
Part A
We will use the next formula to calculate the speed
[tex]v=\sqrt[]{\frac{G\cdot M}{R}}[/tex]where v is the speed, G is the gravitation constant, M is the mass and r is the radius
First, we need to convert the miles to meters
1 mile =1609m
Height of the orbit = 300 miles= 482700 m
The radius of the Earth = 6.37x10^6m
The radius of the Orbit, R = 6.37x10^6+482700=6852700m
M=5.98x10^24 kg
G= 6.673 × 10-11 N.m^2 / kg^2
Then we substitute
[tex]v=\sqrt[]{\frac{(6.673\times10^{-11})(5.98\times10^{24})}{6852700}}=7630.98\text{ m/s}[/tex]Part B
For the period T
[tex]T=\frac{2\pi R}{v}[/tex]We substitute the values
[tex]T=\frac{2\pi(6852700)}{7630.98\text{ }}=5642.4s[/tex]ANSWER
Part A
7630.98 m/s
Part B
5642.4 s
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