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Sagot :
The number of turns on each coil and the voltage in each coil are related by the equation:
[tex]\frac{N_s}{N_p}=\frac{E_s}{E_p}[/tex]Where Ns is the number of turns in the secondary coil, Np is the number of turns on the primary coil, Ep is the voltage in the primary coil and Es is the voltage in the second coil (the outgoing voltage). In this case we know that:
[tex]\begin{gathered} N_s=50 \\ N_p=100 \\ E_p=20 \end{gathered}[/tex]Plugging these values on the equation and solving for Es we have:
[tex]\begin{gathered} \frac{50}{100}=\frac{E_s}{20} \\ E_s=20(\frac{1}{2}) \\ E_s=10 \end{gathered}[/tex]Therefore, the outgoing voltage is 10 V and the answer is c
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