Given,
The mass of the ball, m=16 g=16×10⁻³ kg
The length of the string, r=1.4 m
The period of revolution of the ball, T=1.09 s
The angular velocity of the ball is given by,
[tex]\omega=\frac{2\pi}{T}[/tex]
On substituting the known values,
[tex]\begin{gathered} \omega=\frac{2\pi}{1.09} \\ =5.76\text{ rad/s} \end{gathered}[/tex]
The tension on the string will be equal to the centrifugal force that acts on the ball.
And it is given by,
[tex]F=m\omega^2r[/tex]
On substituting the known values,
[tex]\begin{gathered} F=16\times10^{-3}\times5.76^2\times1.4 \\ =0.74\text{ N} \end{gathered}[/tex]
Thus the magnitude of the tension of the string is 0.74 m
