Answered

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Given v = 520 sin (30t - 5π/4), what is the frequency?Question 13 options:15 Hz30 Hz4.8 Hz19.1 Hz

Sagot :

a The frequency of the sin(x) depends on the period

If the wave has period = 2pi, then the frequency is 1

The frequency of sin(2x) is 2

The given equation is

[tex]v=520\sin (30t-\frac{5\pi}{4})[/tex]

Since the frequency = 2pi/period

Since the period = 2pi/30 = pi/15

Then

[tex]\begin{gathered} F=\frac{2\pi}{\frac{\pi}{15}} \\ F=2\pi\times\frac{15}{\pi} \\ F=2\times15 \\ F=30\text{ HZ} \end{gathered}[/tex]

The frequency is 30 Hz

The answer is B

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