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A 4.0 L container holds a sample of hydrogen gas at 296 K and 130 kPa.If the pressure increases to 380 kPa and the volume remains constant, what will the new temperature be?Round your answer to one decimal place.

Sagot :

Explanation:

We are given: volume = 4 L constant

: Initial temperature = 296K

: Initial pressure = 130kPa

: Final pressure = 380kPa

To find the final temperature, we use:

[tex]\begin{gathered} \frac{P_1}{T_1}\text{ = }\frac{P_2}{T_2} \\ \\ \therefore T_2\text{ = }\frac{P_2T_1}{P_1}\text{ = }\frac{380\text{ }\times\text{ 296}}{130}\text{ = 865.2K} \end{gathered}[/tex]

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