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An aircraft flies due north from airport X toY and then flies due west to Z. If Y is equidistant from X and Z, calculate the bearingof X from z

Sagot :

Explanation

We are required to determine the bearing of X from Z from theh given information.

This is achieved thus:

From the diagrammatic representation, let d km represent the equal distance from Y to X and from Y to Z.

According to angle Z, we have:

[tex]\begin{gathered} \tan\theta=\frac{opposite}{adjacent} \\ \tan Z=\frac{d}{d} \\ tanZ=1 \\ Z=\tan^{-1}(1) \\ Z=45\degree \end{gathered}[/tex]

Therefore, the bearing of X from Z is:

[tex]\begin{gathered} Bearing=90\degree+45\degree \\ Bearing=135\degree \end{gathered}[/tex]

Hence, the answer is:

[tex]135\degree[/tex]

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