Answered

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2.Solve the given equation over the interval [0, 2.x): 2 sin2 x - sin x = 0.7% 11%x= 0 and x= and x=662 20x = 0 and x= - and x =3ग57x = 0 and x = - and x =664557x= 0 and x=and x =33

Sagot :

It is given that

[tex]\begin{gathered} 2\sin ^2x-\sin x=0 \\ \sin x(2\sin x-1)=0 \\ \sin x=0,2\sin x-1=0 \\ \sin x=0,\sin x=\frac{1}{2} \end{gathered}[/tex]

Therefore in the interval

[tex]\lbrack0,2\pi)[/tex]

sin function takes the value 0 at

[tex]x=0,x=\pi[/tex]

It takes the value of 0.5 at

[tex]x=\frac{\pi}{6},\frac{5\pi}{6}[/tex]

Therefore the above four values are correct

Option C is correct.

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