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Sagot :
Given:
• Vertical drop = 95 meters
,• Initial velocity = 0 m/s
,• Mass of cart and riders = 1000 kg
,• Final velocity = 35 m/s
Let's find the amount of potential energy converted to thermal energy.
For the potential energy, we have:
PE = mgh
Also thermal energy is a form of kinetic energy.
Thus, for the thermal energy, we have:
[tex]KE=\frac{1}{2}mv^2[/tex]Now, to find the difference, we have:
[tex]\begin{gathered} PE-KE \\ \\ =(\text{mgh)}-(\frac{1}{2}mv^2) \end{gathered}[/tex]Where:
g is acceleration due to gravity = 9.8 m/s^2
v is the final velocity = 35 m/s
h is the height = 95 meters
m is the mass
Thus, we have:
[tex]\begin{gathered} (1000\times9.8\times95)-(\frac{1}{2}\times1000\times35^2) \\ \\ =931000-612500 \\ \\ =318500\text{ J }\approx319000\text{ }\approx319\text{ kJ} \end{gathered}[/tex]Therefore, the amount of potential energy converted into thermal energy is 319 kiloJoules.
ANSWER:
319 kJ
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