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Sagot :
Given the following function
[tex]f(x)=x^2(x+10)(x-10)[/tex]We want to know the maximum number of turning points of this function. To determinate the maximum number of turning points, first we need to understand what is a turning point.
A turning point is is a point where the first derivative is null.
To find the turning points then, we just need to calculate the first derivative and solve for f'(x) = 0.
To find the derivative, we can just expand the polynomial and use the power rule.
[tex]x^2(x+10)(x-10)=x^2(x^2-100)=x^4-100x^2_{}[/tex][tex]f^{\prime}(x)=4x^3-200x[/tex]Now, we just need to solve for f'(x) = 0 to find the turning points, but, since we only want to know the maximum amount of turning points is even easier to find. This is a third-degree polynomial, and the solutions for the f'(x) = 0 are the roots of this polynomial. Since it is a third-degree polynomial, the maximum amount of roots is 3.
From the statements of item C, we can see the correct graph is the graph C.
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