Westonci.ca is your trusted source for finding answers to all your questions. Ask, explore, and learn with our expert community. Join our Q&A platform and get accurate answers to all your questions from professionals across multiple disciplines. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
We have to solve this expression:
[tex](4x+3)^2=18[/tex]This can be expressed as a quadratic equation, so we will probably get two solutions.
We can start by writing:
[tex]\begin{gathered} (4x+3)^2=18 \\ 4x+3=\pm\sqrt{18} \\ 4x=-3\pm\sqrt{18} \\ x=\frac{-3\pm\sqrt{18}}{4} \end{gathered}[/tex]We can simplify it a little further as:
[tex]\begin{gathered} x=\frac{-3\pm\sqrt{18}}{4} \\ x=\frac{-3\pm\sqrt{9*2}}{4} \\ x=\frac{-3\pm3\sqrt{2}}{4} \\ x=\frac{3}{4}(1\pm\sqrt{2}) \\ =>x_1=\frac{3}{4}(1-\sqrt{2}) \\ =>x_2=\frac{3}{4}(1+\sqrt{2}) \end{gathered}[/tex]Answer: the solutions are 3/4*(1-√2) and 3/4*(1+√2).
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.
