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If you choose a number from the sample below, what is the probability of picking an odd number? (give answer as a percentage rounded to the nearest tenth) S = (3, 12, 15, 9,5, 14, 21, 17, 19) P(odd)

Sagot :

ANSWER

P(odd) = 77.8%

EXPLANATION

The probability of an event occuring is gotten by dividing the number of outcomes of that event (in a sample space) by the total number of outcomes in the sample space.

This means that to find the probabilty of picking an odd number, we have to divide the number of odd numbers by the total numbers in the sample space.

In the sample space given, there are 7 odd numbers and a total of 9 numbers.

Therefore, the probability of getting an odd number is:

[tex]\begin{gathered} P(\text{odd) = }\frac{7}{9} \\ \text{Converting to percentage:} \\ P(\text{odd) = }\frac{7}{9}\cdot\text{ 100} \\ P(\text{odd) = 77.8\%} \end{gathered}[/tex]

That is the answer.