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Sagot :
Perimeter of a rectangle = 2l + 2w
where l=length and w =width
From the question;
perimeter= 328m
l= 88m
substitute the values into the formula and then solve for w
328 = 2(88) + 2w
328= 176 + 2w
subtract 176 from both-side of the equation
328 - 176= 2w
152 = 2w
Divide both-side of the equation by 2
152/2 = w
76 = w
The width is 76 m
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