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1. Inte the size of angle Mae a fraction, Then we decimal rounded to the 8-20

Sagot :

In the given right triangle LMN

N is the right angle, then LM is the hypotenuse

For angle M

The opposite side to it is LN

Then

[tex]\sin M=\frac{LN}{LM}[/tex]

LN = 8 and LM = 10

[tex]\sin M=\frac{8}{10}=\frac{4}{5}[/tex]

The adjacent side is NM

[tex]\cos M=\frac{NM}{LM}[/tex]

NM = 5 and LM = 10

[tex]\cos M=\frac{5}{10}=\frac{1}{2}[/tex]

For angle L

The opposite side is MN

[tex]\sin L=\frac{MN}{LM}[/tex][tex]\sin L=\frac{5}{10}=\frac{1}{2}[/tex]

The adjacent side is LN

[tex]\cos L=\frac{LN}{LM}[/tex][tex]\cos L=\frac{8}{10}=\frac{4}{5}[/tex]

From the answers above

Sin M = 4/5 and cos L = 4/5, then

5) sin M is equal to cos L

and also cos M = sin L

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