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Sagot :
In the given right triangle LMN
N is the right angle, then LM is the hypotenuse
For angle M
The opposite side to it is LN
Then
[tex]\sin M=\frac{LN}{LM}[/tex]LN = 8 and LM = 10
[tex]\sin M=\frac{8}{10}=\frac{4}{5}[/tex]The adjacent side is NM
[tex]\cos M=\frac{NM}{LM}[/tex]NM = 5 and LM = 10
[tex]\cos M=\frac{5}{10}=\frac{1}{2}[/tex]For angle L
The opposite side is MN
[tex]\sin L=\frac{MN}{LM}[/tex][tex]\sin L=\frac{5}{10}=\frac{1}{2}[/tex]The adjacent side is LN
[tex]\cos L=\frac{LN}{LM}[/tex][tex]\cos L=\frac{8}{10}=\frac{4}{5}[/tex]From the answers above
Sin M = 4/5 and cos L = 4/5, then
5) sin M is equal to cos L
and also cos M = sin L
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