ANSWER:
A.
[tex]\frac{2y^4}{x^4}[/tex]
STEP-BY-STEP EXPLANATION:
We have the following expression:
[tex]\frac{14x^4y^6}{7x^8y^2}[/tex]
We simplify and we are left with the following:
[tex]\begin{gathered} \text{ We follow the following property:} \\ \\ \frac{x^a}{x^b}=x^{a-b} \\ \\ \text{ Therefore:} \\ \\ \frac{14}{7}=2 \\ \\ \frac{x^4}{x^8}=x^{4-8}=x^{-4}=\frac{1}{x^4} \\ \\ \frac{y^6}{y^2}=y^{6-2}=y^4 \\ \\ \frac{14x^4y^6}{7x^8y^2}=2\cdot y^4\cdot\frac{1}{x^4}=\frac{2y^4}{x^4} \end{gathered}[/tex]
The correct option is then A
