Answered

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How many solutions does the following equation have? 4(y+z+ 2) = 716 (2+ y)

How Many Solutions Does The Following Equation Have 4yz 2 716 2 Y class=

Sagot :

Problem

How many solutions does the following equation have? 4(y+z+ 2) = sqrt(16) (2+ y)​

Solution

For this case the first step would be distribute the terms in the equation and we got:

4y +4z +8 = 8 +4y

We can subtract in both sides 4y and we got:

4z +8= 8

Then we can subtract 8 in both sides and we got:

4z = 0

z=0

Then if z=0 y can be any number so then we have infinite solutions for this case

Infinite

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