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Hello I have no idea how to solve this question. Balanced equation: 2C8H18 + 25O2 = 16CO2 + 18H2O

Hello I Have No Idea How To Solve This Question Balanced Equation 2C8H18 25O2 16CO2 18H2O class=

Sagot :

Explanation

Given

[tex]2C_8H_{18}+25O_2\rightarrow16CO_2+18H_2O[/tex]

Mass of O2 = 500 g

Required: Mass of CO2 and H2O that will be produced.

Solution

CO2 that will be produced.

Step 1: Find the moles of O2

n = m/M where n is the moles, m is the mass and M is the molar mass

n = 500 g/31.998 g/mol

n = 15.63 mol

Step 2: Use the stoichiometry to find moles of CO2

The molar ratio between O2 and CO2 is 25:16

Therefore the moles of CO2 = 15.63 x (16/25) = 10.00 mol

Step 3: Calculate the mass of CO2 that will be produced.

m = n x M

m = 10.00 mol x 44,01 g/mol

m = 440.13 g

H2O mass that will be produced

Step 1: Use the stoichiometry to find moles of H2O

The molar ratio between O2 and H2O is 25:18

Therefore the moles of CO2 = 15.63 x (18/25) = 11.25 mol

Step 3: Calculate the mass of H2O that will be produced.

m = n x M

m = 11.25 mol x 18.01528 g/mol

m = 203 g

Answers

Mass of CO2 = 440 g

Mass of H2O = 203 g

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