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ab^3 - 9ab/12ab^2+ 12ab - 144a

Sagot :

Given

[tex]\frac{ab^3-9ab}{12ab^2+12ab-144a}[/tex]

Answer

[tex]\begin{gathered} \frac{ab^3-9ab}{12ab^2+12ab-144a} \\ \frac{ab(b^2-9)}{12a(b^2+b-12a)} \\ \frac{b(b-9)(b+9)}{12(b^2+b-12a)} \end{gathered}[/tex]