Answered

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Find the equation of the line that has a slope of 2 and contains the point (3, 5).

Sagot :

The equation of a line in slope-intercept has the following form:

y = mx + b

Where m is the slope of the line and b is the y-intercept.

By replacing 2 for m, we get:

y = 2x + b

By replacing the x and y-coordinates of the point where the line passes through (3, 5), we get:

5 = 2(3) + b

5 = 6 + b

From this equation we can solve for b to get:

5 - 6 = 6 - 6 + b

-1 = b

b = -1

Then, the equation of the line is:

y = 2x - 1

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