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Sagot :
The first step to solve this problem is using the molecular mass of ethyleneglycol to find the mass of 0.350moles of this compound.
[tex]0.350mol\cdot\frac{62.07g}{mol}=21.7245g[/tex]Use the percent by mass to find the mass of the solution, remember that there are 56g of ethyleneglycol for every 100g of solution:
[tex]21.7245g\cdot\frac{100g}{56g}=38.79375g[/tex]Use the density of the solution to find how many mililiters contain the estimated mass of solution :
[tex]38.79375g\cdot\frac{ml}{1.072g}=36.18ml[/tex]The volume of solution that contains 0.350 moles of ethylene glycol is 36.18ml.
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