Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Get immediate and reliable answers to your questions from a community of experienced experts on our platform. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

write the linear equation that passes through the point (-6,1) with a slow of 1/2.

Write The Linear Equation That Passes Through The Point 61 With A Slow Of 12 class=

Sagot :

Answer:

y = 1/2 x + 4

Explanation:

The slope intercept form of an equation is

[tex]y=mx+b[/tex]

where m is the slope and b is the y-intercept.

Now in our case the slope m = 1/2; therefore,

[tex]y=\frac{1}{2}x+b[/tex]

Now we just need to find the value of b.

Luckily we are told that the line passes through the point (-6, 1), which means that the above equation must satisfy x = -6 given y = 1.

Putting in x = -6 and y = 1 in the above equation gives

[tex]1=\frac{1}{2}(-6)+b[/tex]

which simplifies to give

[tex]1=-3+b[/tex]

adding 3 to both sides gives

[tex]\begin{gathered} 1+3=-3+b+3 \\ 4=b \end{gathered}[/tex]

Hence, the value of b is 4, and therefore, our equation becomes

[tex]\boxed{y=\frac{1}{2}x+4}[/tex]

which is our answer!