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Sagot :
Answer
20.8 moles of H₂O
Explanation
Given:
The moles of iron(III) oxide produced = 5.2 mol
Equation: 3Fe(s) + 4H2O(l) ⇨ Fe3O4(s) + 4H2(g)
What to find:
The moles of water required to produce 5.2 moles of iron(III) oxide.
Solution:
Using the mole ratio of water to iron (iii) oxide in the given equation; which is
4 moles of H₂O produced 1 mole of Fe₃O4
So, x moles of H₂O will produce 5.2 moles of Fe₃O4
[tex]\begin{gathered} x=\frac{5.2mol\text{ }Fe_3O_4}{1mol\text{ }Fe_3O_4}\times4mol\text{ }H_2O \\ \\ x=20.8mol\text{ }H_2O \end{gathered}[/tex]Hence, the moles of water required to produce 5.2 moles of iron(III) oxide is 20.8 moles
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