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What is the percent composition of zinc phosphate (Zn3(PO4)2)? Find the percentage for each element.

What Is The Percent Composition Of Zinc Phosphate Zn3PO42 Find The Percentage For Each Element class=

Sagot :

Answer:

Percentage of zinc = 50.81%

Percentage of Phosphorous = 16.05%

Percentage of oxygen = 33.14%

Explanations:

The molecular formula of zinc phosphate is given as:

[tex]Zn_3\mleft(PO_4\mright)_2[/tex]

To get the percentage of each element in the compound, we will apply the formula:

[tex]\%\text{composition = }\frac{molar\text{ mass of the element}}{molar\text{ mass of the compound}}\times100[/tex]

Get the molar mass of the compound.

Given the molar masses of the elements

Zinc = 65.38g/mol

Phosphorous = 30.97g/mol

Oxygen = 15.99g/mol

[tex]\begin{gathered} \text{Molar mass of }\mleft(Zn_3\mleft(PO_4\mright)_2\mright)=3(65.38)+2(30.97)+8(15.99) \\ \text{Molar mass of }(Zn_3(PO_4)_2)=196.14+61.94+127.92 \\ \text{Molar mass of }(Zn_3(PO_4)_2)=386\text{g/mol} \end{gathered}[/tex]

Get the percentage composition by mass of each element:

For Zinc element;

[tex]\begin{gathered} \%\text{ of Zn = }\frac{196.14}{386}\times100 \\ \%\text{ of Zn }=50.81\% \end{gathered}[/tex]

For Phosphorous element

[tex]\begin{gathered} \%\text{ of Phosphorous = }\frac{61.94}{386}\times100 \\ \%\text{ of Phosphorous = }16.05\% \end{gathered}[/tex]

For the oxygen element;

[tex]\begin{gathered} \%\text{ of Oxygen = }\frac{127.92}{386}\times100 \\ \%\text{ of Oxygen }=\text{ }33.14\% \end{gathered}[/tex]

Therefore the percentage composition of Zinc, Phosphorous, and Oxygen in zinc phosphate is 50.81%, 16.05%, and 33.14% respectively