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14 13 B:7-6-5-4-3-2-1 1.213.4.5.6.7.8 INITIAL 도무 WTZ -5 -6 -7 This could be the graph of: V ch M O A. In(x+3) -4 O B. In(x - 3) +4 Ci O c. ln(x+3) O D. In(x) + 4

14 13 B7654321 121345678 INITIAL 도무 WTZ 5 6 7 This Could Be The Graph Of V Ch M O A Inx3 4 O B Inx 3 4 Ci O C Lnx3 O D Inx 4 class=

Sagot :

Let's look at the basic graph of y = ln(x).

The graph is shown below:

The graph shown in the problem is shifted 3 units left and 4 units down, with respect to the parent function (graph shown above).

If we have a function f(x),

• The function f(x + a) is f(x) shifted 'a' units left

,

• The function f(x - a) is f(x) shifted 'a' units right

,

• The function f(x) + a is f(x) shifted 'a' units up

,

• The function f(x) - a is f(x) shifted 'a' units down

Using the translation rules above, we can write the shifted function as,

[tex]\begin{gathered} f(x)=\ln x \\ -------- \\ \text{SHIFTED function is,} \\ y=\ln (x+3)-4 \end{gathered}[/tex]

From the answer choices, "_" is correct.

Answer

_

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