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That data from our recent tests are organized by sex and letter grade use this information to calculate the following probability round solution a 3 decimal places

Sagot :

Part 1

The probability that the student got a C

P=10/69 -------> P=0.145

Part 2

we have that

The probability that the student was a female and got a B

P=12/69 -------> P=0.174

Part 3

The probability that the student was a male or got and A

The probability that the student was a male ------> P=32/69 -----> P=0.464

Probability that the student got an A -----> P=13/69 -----> P=0.188

so

The probability that the student was a male or got and A ----> P=0.464+0.188=0.652

Part 4

P=13/32 ------> P=0.406

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