Answered

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Can you please help me out

Sagot :

Let us begin by getting the area of the small circle

[tex]\begin{gathered} a=\pi r^2 \\ =\pi\times1^2 \\ =\pi \end{gathered}[/tex]

The area of the bigger circle is

[tex]\begin{gathered} A=\pi R^2 \\ =\pi\times6^2 \\ =36\pi \end{gathered}[/tex]

The probability can be calculated as

[tex]\begin{gathered} P=\frac{a}{A} \\ =\frac{\pi}{36\pi} \\ =\frac{1}{36} \end{gathered}[/tex]

The probability of hitting the target in the smallest circle is 1/36.

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