At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Explore a wealth of knowledge from professionals across different disciplines on our comprehensive platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
The length (l) of the pipe = 36ft
The Volume(V) of the pipe = 100 ft³
The diameter(d) of the pipe = ?
[tex]\begin{gathered} \text{ Volume (V) = }\pi r^2l \\ 100\text{ = 3.14 }\times r^2\times36 \\ r^2=\frac{100}{3.14\times36}=0.8846 \\ r^2=0.8846 \\ r=\sqrt[]{0.8846\text{ }}\text{ =0.941 ft} \end{gathered}[/tex]Diameter(d) of the pipe = 2 x radius
= 2 x 0.941 ft
= 1.882ft
Therefore, the approximate diameter of the pipe is 1.882ft to 3 decimal places.
Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.
