Answered

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determine an equation for the line that has a y- intercept 8 of an x intercept of -2 ?

Sagot :

Given:

y-intercept = 8

x-intercept = -2

At y-intercept, x = 0: (0, 8)

At x intercept, y = 0: (-2, 0)

Use the slope intercept form:

y = mx + b

Where m is the slope and b is the y-intercept

To find an equation for the line, first find the slope.

[tex]m=\frac{y2-y1}{x2-x1}[/tex]

Where

(x1, y1) ==> (-2, 0)

(x2, y2) ==> (0, 8)

[tex]m=\frac{8-0}{0--2}=\frac{8}{0+2}=\frac{8}{2}=4[/tex]

The slope is 4

The y-intercept = 8

We have:

y = 4x + b

Therefore, the equation of the line is:

y = 4x + 8

ANSWER:

y = 4x + 8

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