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Final Grade An instructor grades exams, 30%; term paper, 30%; and final exam, 40%. A student had grades of 88, 90, and 96, respectively, for exams, terpaper, and final exam. Find the student's final average. Use the weighted mean.

Sagot :

Answer:

[tex]\bar{x}=91.8[/tex]

Step-by-step explanation:

Grades respectively:

30% Grades exams: 88

30% Term paper: 90

40% Final exam: 96

The weighted mean is represented by the following equation:

[tex]\bar{x}=\frac{\sum ^{}_{}(wx)}{\sum ^{}_{}w}[/tex]

Therefore, the student's final average would be:

[tex]\begin{gathered} \bar{x}=\frac{0.3\cdot88+0.3\cdot90+0.4\cdot96}{1} \\ \bar{x}=91.8 \end{gathered}[/tex]

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