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Sagot :
Answer:
The solutions are -7/2 and 1. Jeffrey is correct.
Step-by-step explanation:
We have to use the Bhaskara formula to solve this question.
Bhaskara formula:
Suppose we have the following second order equation:
ax² + bx + c = 0
The solution of the equation are:
[tex]x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]In this question:
(2x - 1)(x + 3) = 4
We have to apply the distributive property to place the equation in the correct format to apply Bhaskara.
(2x - 1)(x + 3) = 4
2x² + 6x - x - 3 = 4
2x² + 5x - 3 - 4 = 0
2x² + 5x - 7 = 0
[tex]x=\frac{-5\pm\sqrt{(5)^2-4\ast2\ast(-7)}}{2\ast2}=\frac{-5\pm\sqrt{25+56}}{4}=\frac{-5\pm\sqrt{81}}{4}=\frac{-5\pm9}{4}[/tex]The solutions are:
[tex]x^{^{\prime}}=\frac{-5+9}{4}=1[/tex][tex]x^{^{\prime\prime}}=\frac{-5-9}{4}=-\frac{14}{4}=-\frac{7}{2}[/tex]The solutions are -7/2 and 1. Jeffrey is correct.
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