14.
Answer:
The solution to the equation is;
[tex]y=40[/tex]
Explanation:
Given the equation;
[tex]11\mleft(4-6y\mright)+5\mleft(13y+1\mright)=9[/tex]
To solve, let us expand the bracket;
[tex]\begin{gathered} 11\mleft(4-6y\mright)+5\mleft(13y+1\mright)=9 \\ 11(4)-11(6y)+5(13y)+5(1)=9 \\ 44-66y+65y+5=9 \end{gathered}[/tex]
Simplifying and collecting the like terms;
[tex]\begin{gathered} 44-66y+65y+5=9 \\ -y+5+44=9 \\ -y+49=9 \end{gathered}[/tex]
subtract 49 from both sides;
[tex]\begin{gathered} -y+49-49=9-49 \\ -y=-40 \end{gathered}[/tex]
divide both sides by -1;
[tex]\begin{gathered} \frac{-y}{-1}=\frac{-40}{-1} \\ y=40 \end{gathered}[/tex]
Therefore, the solution to the equation is;
[tex]y=40[/tex]