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Which equation represents a line which is perpendicular to the line y=2/5x-81. y=2/5x-32. y=5/2x-13. y=-2/5x+64. y=-5/2x+9

Sagot :

The slope-intercept form of the line is given by:

[tex]\begin{gathered} y=mx+b \\ m=slope \\ b=y-intercept \end{gathered}[/tex]

for the line:

[tex]y=\frac{2}{5}x-8[/tex][tex]m=\frac{2}{5}[/tex]

If two lines are perpendicular, then:

[tex]\begin{gathered} m1\times m2=-1 \\ so\colon \\ \frac{2}{5}\times m2=-1 \\ m2=-\frac{1}{\frac{2}{5}} \\ m2=-\frac{5}{2} \end{gathered}[/tex]

Therefore, the equation that represents the line perpendicular to the line y = 2/5x - 8 is:

[tex]y=-\frac{5}{2}x+9[/tex]